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Lynna [10]
2 years ago
10

Can anyone help me figure this out / explain it to me pls .. ="(

Mathematics
1 answer:
Bad White [126]2 years ago
8 0
Um I think your teacher might be high
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What is the equation of the line that passes through the point (5, 6) and has a slope<br> of 2
Mrac [35]

Answer:

y = 2x - 4

Step-by-step explanation:

Given:

x1 = 5

y1 = 6

slope (m) = 2

Solution:

y - y1 = m ( x - x1 )

y - 6 = 2 ( x - 5 )

y - 6 = 2x - 10

y = 2x - 10 + 6

y = 2x - 4

6 0
2 years ago
The width of a rectangle is 3 more than twice its length. the area is 35 square meters what is the length of the rectangle
defon
35=3L+3
3L=32
L=10\frac{2}{3}
THE LENGTH OF THE RECTANGLE IS 10 AND TWO THIRD METERS.
10\frac{2}{3}+2(10\frac{2}{3})+3=35
6 0
3 years ago
Sweatshirts at the discount store are on sale for 30% off the original price. If a sweatshirt
kobusy [5.1K]
A.) the discount is $9
B.) the new price is $21

Work:
30% is turned to .30
so, $30 x .30 is $9.
that’s how much is taken off.
3 0
3 years ago
Find the slope of the line that passes through (-2,1) (7,1)​
stich3 [128]

Answer:

0

Step-by-step explanation:

To find the slope of a line, we uses y2-y1/x2-x1:

y2-y1/x2-x1

1-1/7+2

0/9

0

The slope of the line is 0.

<em>If u have any questions about what I did feel free to ask in the comments!</em>

3 0
2 years ago
Read 2 more answers
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
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