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raketka [301]
3 years ago
15

Which skier the most potential energy?

Mathematics
2 answers:
enyata [817]3 years ago
5 0
It is c

Plz give pointsssss
Ghella [55]3 years ago
5 0
C there just different color
You might be interested in
Covert this rational number to its decimal form and round to the nearest thousandth. 7/9​
Lisa [10]

Answer:

0.778 to the nearest thousandth.

Step-by-step explanation:

Dividing 7 by 9:    

9) 7.000000

   0.7777777 ....   <--    quotient

So it is 0.778 to the nearest thousandth.

3 0
2 years ago
2/3 divided by 5?If she walks 2/3 by another 5.
Nadya [2.5K]

Answer:

The answer is 0.133

Step-by-step explanation:

All you have to do is take 2/3 as if it was a whole number and divide it by 5, or if you are able to use a calculator, you can just but it in as 2 divided by 3 and then divide 5 by whatever answer you get.

7 0
4 years ago
Read 2 more answers
Make h the subject of the formula<br><br> t=gh/10
Lera25 [3.4K]
Here, t = gh/10
gh = 10t
h = 10t/g

In short, Your Answer would be 10t / g

Hope this helps!
7 0
3 years ago
Evaluate each function at the given value <br> f(n) = n ^ 4 + 5n ^ 3 + 2n ^ 2 - 5n + 13 at n = - 2
DedPeter [7]

Answer:

  • 7

Step-by-step explanation:

<h3>Given</h3>
  • f(n) = n ^ 4 + 5n ^ 3 + 2n ^ 2 - 5n + 13
<h3>To find </h3>
  • f(-2)
<h3>Solution</h3>

<u>Substituting n with -2</u>

  • f(-2) =
  • (-2)^4 + 5(-2)^3 + 2(-2)^2 - 5(-2) + 13 =
  • 16 - 40 + 8 + 10 + 13 =
  • 7
3 0
3 years ago
A random number is selected from the interval [6.35, 10]. Find the probability that the number is within a distance of 0.25 from
exis [7]

Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

f_X(x)=\begin{cases}\dfrac1{10-6.35}=\dfrac1{3.65}\approx0.2740&\text{if }6.35\le x\le 10\\0&\text{otherwise}\end{cases}

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)

… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)

… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)

(since P(<em>X</em> > 10) = 0)

… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

… = 0.2055

6 0
3 years ago
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