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erica [24]
3 years ago
5

A stone is dropped vertically downwards. What is the velocity of the rock after 4 seconds ? What is the displacement of the rock

after 4 seconds ?
Physics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

Vf = 39.2 m/s

h = 78.4 m

Explanation:

Using first equation of motion for vertical motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t = time taken = 4 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(4 s)

<u>Vf = 39.2 m/s</u>

<u></u>

Now, we use second equation of motion

h = Vi t + (1/2)gt²

where,

h = height covered = ?

Therefore,

h = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²

<u>h = 78.4 m</u>

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Given:

Speed of the speed 2.9 m/s

The direction in which the inertia change is moving = 43° north west.

Time taken to travel the distance = 30 minutes

According to the question that is moving in a Northwest direction with a velocity of 2.9 m per second.

If you want to find the distance it has moved in either North or west direction you will first have to find the total distance that kayak has moved in 30 minutes.

The distance travel by the kayak in 30 minutes = speed of person × time taken

The distance travel by the person in 30 minutes = 2.9 × 30 × 60

The distance travel by the person in 30 minutes = 5220 metre

The distance travel by the person in 30 minutes = 5.22 km

The distance traveled in the west direction can be find using trigonometric ratio.

5.2 × sin 43 = The distance traveled in the west direction

The distance traveled in the west direction = 3.6 kilometers

The distance traveled in the west = cos 43 × 5.2

The distance traveled in the west = 2.35 km

Therefore, The person with the speed of 2.9 m/s has moved a distance of 3.6 kilometers in the west direction and 2.35 kilometers in the north direction.

Learn more about the trigonometric ratio here:

brainly.com/question/26719838

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2 years ago
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Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
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Answer:

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q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

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Answer:

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