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docker41 [41]
2 years ago
11

URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS

Physics
1 answer:
lubasha [3.4K]2 years ago
6 0

The inertia with the speed of 2.9 m/s has moved a distance of 3.6 kilometers in the west direction and 2.35 kilometers in the north direction.

<h3>What are trigonometric ratio?</h3>

In mathematics, the trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths. They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others.

Given:

Speed of the speed 2.9 m/s

The direction in which the inertia change is moving = 43° north west.

Time taken to travel the distance = 30 minutes

According to the question that is moving in a Northwest direction with a velocity of 2.9 m per second.

If you want to find the distance it has moved in either North or west direction you will first have to find the total distance that kayak has moved in 30 minutes.

The distance travel by the kayak in 30 minutes = speed of person × time taken

The distance travel by the person in 30 minutes = 2.9 × 30 × 60

The distance travel by the person in 30 minutes = 5220 metre

The distance travel by the person in 30 minutes = 5.22 km

The distance traveled in the west direction can be find using trigonometric ratio.

5.2 × sin 43 = The distance traveled in the west direction

The distance traveled in the west direction = 3.6 kilometers

The distance traveled in the west = cos 43 × 5.2

The distance traveled in the west = 2.35 km

Therefore, The person with the speed of 2.9 m/s has moved a distance of 3.6 kilometers in the west direction and 2.35 kilometers in the north direction.

Learn more about the trigonometric ratio here:

brainly.com/question/26719838

#SPJ9

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A car is moving 14.4 m/s. It decelerates at -1.55 m/s^2 for 4.26 s. It then accelerates at 1.83 m/s^2 until it reaches 11.8 m/s.
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The total time is 6.45 s

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use suvat equations.

In the first part,

u_1 = 14.4 m/s (initial velocity)

a_1 = -1.55 m/s^2 (acceleration)

t_1=4.26 s (time of the first part)

So, we can find the velocity of the car after the first part, by using

v_1 = u_1 +a_1 t_1 =14.4+(-1.55)(4.26)=7.8 m/s

This is therefore the initial velocity of the second part:

u_2 = v_1 = 7.8 m/s

a_2 = 1.83 m/s^2 (acceleration in the second part)

v_2 = 11.8 m/s (final velocity)

And therefore,

v_2 = u_2 + a_2 t_2\\t_2=\frac{v_2-u_2}{a_2}=\frac{11.8-7.8}{1.83}=2.19 s

So, the total time is

t=t_1+t_2=4.26+2.19=6.45 s

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