Height of the rocket will be <span>h(t)=−<span>12</span>g<span>t2</span>+<span>v0</span>tsinθ+<span>h0</span></span> where
<span>g=9.8<span> m/s2</span></span>
<span><span>v0</span>=86 m/s</span>
<span><span>h0</span>=0 m</span>
<span>θ= angle formed with the vertical
</span>
That's a parabola. You'll solve that for <span>h(<span>tf</span>)=0</span> to find the time of flight.
The horizontal component of the rocket's velocity will be <span><span>vx</span>=<span>v0</span>cosθ</span>. You know that <span>x=<span>vx</span><span>tf</span>=104 m</span> where <span>tf</span> is the time of flight. You can use that relationship to write an expression for <span>tf</span> in terms of <span>v0</span> and θ. Substitute that into the first equation and solve for θ.
Once you've got the parabola figured out, you can easily find the maximum height by finding the vertex, and you've already found the duration of the flight.
Answer:
C
Explanation:
lightning is an electrostatic discharge
The force exerted(applied) onto a surface by the weight of air
Answer:
C
Explanation:
horizintal speed stays same
only vertical speed changes
so H speed will stay 30 m/s
Acceleration is the rate of
change of the velocity of an object that is moving. This value is a result of
all the forces that is acting on an object which is described by Newton's
second law of motion. <span>Calculation of such is
straightforward, if we are given the final velocity, the initial velocity and
the total time interval. We can just use the kinematic equations. Fortunately, we are given these values. So, we calculate as follows:
</span>
acceleration = v - v0 / t
acceleration = (80 mph - 50 mph) ( 1 h / 3600) / 5 s
acceleration = 1.67 x 10^-3 m / s^2
Therefore, the acceleration of the car is 1.67 x 10^-3 m / s.
