Question

Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the charge on each electrode and the potential difference between them?

Answer 1

Answer:

The charge on each electrode is

$q=0.354 x10^{-12}$

Explanation:

The charge to find the equation is development

V=9v

$d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )$

$q=C*V$

$C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4} }{0.01}=0.354$

$q=0.354*9v\\q=3.186x10^{-12} C$