All categories

3 years ago

what do i write for this " Write a problem that requires adding 1 to the quotient when interpreting the remainder."

1 answer:

6 0

You should write a ( real world situation ) question that can only have whole numbers as a solution because you would divide and then you can not have a fraction left over so instead you add one. For instance there are 132 students going on a field trip. 20 students can fit on each bus. how many buses are needed? 7 because when you divide 132 by 20 you get 6 remainder 12. You can not just make 12 students walk to the location so you would add an extra bus.

You might be interested in

john is placing cement tiles for a patio in a rectangle surrounding a rectangular fire pit. The fire pit has a width of x ft and

Finger [1]

Answer:

49x + 114

Step-by-step explanation:

[ [ fireplace ] x = area of 5 $x^{2}$ ] x + 6

patio = area of 5 $x^{2}$ + 49x + 114

5x + 19

(5x + 19) ( x + 6) = 5 $x^{2}$ + 19x + 30x + 114

(5 $x^{2}$ + 49x + 114) - (5 $x^{2}$ ) = 49x + 114

(area of patio and fireplace) - (area of fireplace) = (area of patio only)

4 0

2 years ago

What are the solutions of the quadratic equation below?

Maurinko [17]

The answer is A
its a simple eqaution carry the 1 over

8 0

3 years ago

Read 2 more answers

Solve the equation. 2(5c – 7) = 1

liq [111]

$\text{Hello there!}\\\\\text{Solve for c:}\\\\2(5c -7) = 1\\\\\text{First, distribute the 2}\\\\10c-14=1\\\\\text{Add 14 to both sides}\\\\10c=15\\\\\text{Divide both sides by 10}\\\\c=1.5\\\\\boxed{\text{Answer: c = 1.5 or 3/2}}$

8 0

3 years ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

1x10 to the fifth power over 4x10 to the negative faith power given on scientific notation

MissTica

Answer:

$2.5*10^{8}$

Step-by-step explanation:

The correct question is

1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation

we know that

To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.

we have

$\frac{1*10^{5}}{4*10^{-4}}=(\frac{1}{4})*10^{5+4} =0.25*10^{9}= 2.5*10^{8}$

8 0

3 years ago