3 years ago

Could someone please help me with this?

Mathematics

2 answers:

abruzzese [7]3 years ago

7 0

I’m alive but I’m dead. Sad :( rip x

Georgia [21]3 years ago

5 0

Here’s the correct answer and how I got it :)

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Tom [10]

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3 years ago

What is the lim of (((1/x)-(1/2))/x-2) , as x approaches 2

Katyanochek1 [597]

I assume the denominator is $x-2$ .

$\lim_{x\to2}\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=\\
\lim_{x\to2}\dfrac{\dfrac{2}{2x}-\dfrac{x}{2x}}{x-2}=\\
\lim_{x\to2}\dfrac{\dfrac{2-x}{2x}}{x-2}=\\
\lim_{x\to2}\dfrac{2-x}{2x(x-2)}}=\\
\lim_{x\to2}-\dfrac{x-2}{2x(x-2)}}=\\
\lim_{x\to2}-\dfrac{1}{2x}}=\\
-\dfrac{1}{2\cdot2}=\\
-\dfrac{1}{4}=
$