You would have to determine if<span> the following </span>lengths<span> make an </span>acute<span>, right or </span>obtuse triangle<span>. Plug in each set of </span>lengths<span> into the Pythagorean Theorem.</span>
        
             
        
        
        
Yes this is the correct answer. The slope field shown is the differential equation dy/dx = x+y
All points along the line x+y = k, for some constant k, will have the same tangent slope k. For example, the line x+y = 0 will have every point with tangent slope 0 for the solution y(x). It may not be 100% clear, but this graph has horizontal tickmarks on the line x+y = 0, or the tickmarks are close to being horizontal. Using geogebra, I checked the others and they produced completely different graphs, which allowed me to rule them out.
        
             
        
        
        
Answer:
I had x to be 2
Step-by-step explanation:
a square has all it side to be equal 
so 10x=6x+8 
you will group like terms 10x-6x=8 
4x=8 you divide both side by the coefficient of x which is four so X=2
 
        
             
        
        
        
The answer would be 15 +20x. You have to combine like terms.
 
                             2+6+7+20x
                              8+7+20x
                                = 15+ 20x  (answer)