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dem82 [27]
3 years ago
13

What is 6 over 9and 11 over 88​

Mathematics
1 answer:
TEA [102]3 years ago
5 0

Answer:

6 over 9 = 6/9 11 over 88 = 11/88 6/9 = 0.6667(repeating) 11/88 = 0.125

P.S. Dont fall for those link scams! ;)

Hope this helped! If it did, please give me brainliest! It would help a lot! Thanks! :D

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If the Ramirez family deposits $5000 in a savings account at 7.5% interest compounded continuously, how much will be in the acco
GenaCL600 [577]

Answer: The amount is $14794.39 and the interest is $9794.39

Step-by-step explanation: If you deposit <em><u>$5000</u></em><u> </u>into an account paying <em><u>7.5%</u></em> annual interest compounded yearly , how much money will be in the account after <em><u>15 years</u></em>?

To find amount we use formula:

A-P(1+r/n) n*t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

P=$5000, r=7.5, n=1 and, t=15 years

After plugging the given information we have

A= $5000 (1+0.075/1)^1.15

A= 5000 *1.075^15

A=14794.39

To find interest we use formula  A=P+I'

since A= 14794.39  and P=5000

we have: A=P+I 14794.39=5000+I

I= 14794.39 -5000

I=9794.39

8 0
3 years ago
Read 2 more answers
Three more than twice the sum of a number and half the number equals 105. Which equation models this relationship?
Umnica [9.8K]

Answer:

The correct answer is A or 2(x+1/2x)=105

Step-by-step explanation:

3+2(x+1/2x)=105

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3 years ago
Find the average of: 15, 8, -22, 24, -9, -18, 16
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The average is 2. To find the average you add all the numbers then divide the sum by the total amount of numbers.
5 0
4 years ago
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Which line segment is a diameter of circle L<br><br> A.GK<br><br> B.HK<br><br> C.IL<br><br> D.JL
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B is the answer because diameter goes all the way through a circle
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3 years ago
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Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
3 years ago
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