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3 years ago

10

Find the value of x.

1 answer:

Gennadij [26K]3 years ago

5 0

Answer:

x=68

Step-by-step explanation:

A²+b²=C²

side a:60²=3600

side b:32²=1024

3600+1024=4624

side c=√4624=68

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SOLVE THIS PLS JSJSXHHX

madam [21]

Step-by-step explanation:

y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

we have multiple function points to use to officially calculate a and b.

1/6 = a×10 + b

2/3 = a×40 + b

5/6 = a×50 + b

1 2/3 = a×100 + b

let's e.g subtract equation 1 from equation 3.

4/6 = a×40 + 0

a = 4/40 / 6 = 4 / 240 = 1/60

1/6 = 10/60 + b

1/6 = 1/6 + b

b = 0

so, the function is

y = x/60

x = 25

y = 25/60 = 5/12 cups

5 0

3 years ago

Find the midpoint of the segment with the given endpoints. (9.-9) and (2.-10)

kondor19780726 [428]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{(5.5 \: , \: - 9.5)}}}}}$

Step-by-step explanation:

Let the points be A and B

Let A ( 9 , -9 ) be ( x₁ , y₁ ) and B ( 2 , - 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the</u><u> </u><u>midpoi</u><u>nt</u>

$\boxed{ \sf{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} }}$

$\longrightarrow{ \sf{midpoint = ( \frac{9 + 2}{2} , \: \frac{ - 9 + ( - 10)}{2}}} )$

$\longrightarrow{ \sf {midpoint = ( \frac{11}{2} \: , \: \frac{ - 9 - 10}{2}})}$

$\longrightarrow{ \sf{midpoint = (5.5 \: , \: \frac{ - 19}{2}}} )$

$\longrightarrow{ \sf{midpoint = (5.5 \: , - 9.5}})$

Hope I helped!

Best regards! :D

5 0

3 years ago

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

7 0

3 years ago

Given h of x equals negative 2 times the square root of x minus 3 end root, which of the following statements describes h(x)?

Yuliya22 [10]

Using translation concepts, it is found that the correct option regarding the function is:

The function h(x) is decreasing on the interval (3, ∞).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is given by:

$f(x) = \sqrt{x}$

Which increases on (0, ∞).

The translated function is given by:

$g(x) = -2\sqrt{x - 3}$

With the translation, the domain is now (-3, ∞), and the function is decreasing, hence the correct option is given by:

The function h(x) is decreasing on the interval (3, ∞).

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

8 0

2 years ago

PICK ONE!! PHOTO ADDED!!

Alex787 [66]

Answer:

B

Step-by-step explanation:

3 0

2 years ago