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inn [45]
3 years ago
5

This...is confusing

Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0
The answer is 82
Explanation:
180-143 would be the angle measurement of A, add angle measures A and C together, then subtract by 180 to get the missing angle measurement
geniusboy [140]3 years ago
6 0

Answer:

<u>82</u>

Step-by-step explanation:

When finding a triangle's missing angle, you first have to know that all of the angles add up to 180. Then, you add the other sides, and subtract that from 180 to get the missing angle. But in this case... Your missing two... but given one other angle. So, because a straight lines angle is 180, you would take 143 and subtract it from 180 to get the other side. There is also more steps... and sorry for not explaining further... but it would take a pretty long time...

180-143=37

A=37

37+61+_=180

37+61=98

180-98=82

The missing angle is 82 degrees

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4 years ago
∠C and ​ ∠D ​ are vertical angles with m∠C=−x+26 and m∠D=2x−10 . What is m∠D ? Enter your answer in the box.
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8 0
4 years ago
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If each of the following questions were asked to a group of second graders, which question would NOT be a statistical question?
sweet-ann [11.9K]

Answer:

d

Step-by-step explanation:

just makes sense bc they're all in 2nd grade

8 0
3 years ago
The dietitian uses 35 six-ounce glasses and 50 eight-ounce glasses at breakfast. Represent in fraction form the relationship of
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6 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
4 years ago
Read 2 more answers
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