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3 years ago

The first quartile of a data set is 31, and the third quartile is 47. Which of these values in the data set is an outlier?

Mathematics

2 answers:

jarptica [38.1K]3 years ago

5 0

Answer: a.83

Step-by-step explanation:

apoooxe

o-na [289]3 years ago

4 0

The answer to this is D

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Alchen [17]

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3 years ago

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harina [27]

Answer:

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Step-by-step explanation:

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3 years ago

What is the 7th term in the sequence 48,40, 32, 24,

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Take the second term and subtract the first term

40-48 = -8

Take the third term and subtract the second term

32-40 = -8

The common difference is -8

We have the 4th term

The fifth term is

24-8 = 16

The sixth term is 16-8 = 8

The seventh term is 8-8 =0

7 0

3 years ago

Read 2 more answers

Pre-Test

Volgvan

Answer:

A and D

Step-by-step explanation:

Ik what question ur talking about and i hope this helps! :)

8 0

3 years ago

Read 2 more answers

(x^2−x−6x^2−8x+16)/(x2−x−12)

erma4kov [3.2K]

-3 and 4 cannot be the values of x in the given expression

The expression is given as:

$\frac{(x^2-x-6x^2-8x+16)}{(x^2-x-12)}$

Start by equating the denominator to 0

$x^2 - x - 12 = 0$

Expand the above equation

$x^2 - 4x + 3x - 12 = 0$

Factorize the equation

$x(x - 4) + 3(x - 4) = 0$

Factor out x - 4

$(x + 3) (x - 4) = 0$

Split

$(x + 3)= 0\ or\ (x - 4) = 0$

Remove brackets

$x + 3= 0\ or\ x - 4 = 0$

Solve for x

$x =- 3\ or\ x = 4$

Hence, -3 and 4 cannot be the value of x in the given expression