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LenaWriter [7]
3 years ago
6

Who knows how to do this ?

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

hello again

Step-by-step explanation:

i think

\frac{10}{19}

have a nice day

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Please hurry 6of25 and I’m very confused
Setler79 [48]

Answer:

selma

Step-by-step explanation:

she has the lowest gross income

6 0
3 years ago
Find the equation of the line shown.
Ymorist [56]

Answer:

y= -2x+9

Step-by-step explanation:

The equation will be written this way :

y= m*x+c

  • m is the slope
  • c is a constant
  • m =( f(4)-f(2))/(4-2)=(1-5)/2= -4/2 = -2
  • y = -2x+c
  • replace x and y by the coordinates of a point to get c
  • 1= -2*4+c
  • c = 9

y = -2x+9

3 0
3 years ago
Read 2 more answers
The thickness of a block is approximately 2 centimeters. How many blocks are in a stack that is 1,000 millimeters high? ( 1 cm =
dangina [55]

Answer:

1block=2cm

1cm=10mm

therefore 1block=2×10=20

1000÷20=50

=50blocks

5 0
3 years ago
Read 2 more answers
I need help!!
netineya [11]

Answer:

2x +21

Step-by-step explanation:

log_{5} {5}^{(2x - 9)}   +  log_{3} {729}^{5}   \\  \\  =  log_{5} {5}^{(2x - 9)}   +  log_{3} {( {3}^{6} )}^{5}   \\  \\  =  log_{5} {5}^{(2x - 9)}   +  log_{3} { {3}}^{6 \times 5}   \\  \\  =  log_{5} {5}^{(2x - 9)}   +  log_{3} { {3}}^{30}    \\  \\ =(2x - 9)  log_{5} {5} + 30 log_{3} { {3}}   \\  \\  = (2x - 9).1 + 30(1 )\\ ( \because \: log_{a} { {a}}    = 1) \\  \\  = 2x - 9 + 30 \\  \\  = 2x +21

7 0
3 years ago
The ball used in a soccer game may not weigh more than 16 ounces or less
Liono4ka [1.6K]
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
3 0
3 years ago
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