Answer:
Well, the answer is simple. Everybody!
Explanation:
Answer:
#include <iostream>
using namespace std;
int main () {
// for loop execution
int semester_fees=8000;
int b=1;
cout<<"there are 5 years or 10 semester fees breakdown is given below"<<endl;
for( int a = 1; a <=5; a++ ) {
semester_fees = semester_fees*1.03;
cout<<"Semester fees for each of semester"<<b++<<"and"<<b++<<"is:$"<<semester_fees<<endl;
}
return 0;
}
Explanation:
code is in c++ language
Fees is incremented yearly and i have considered only two semester per year
If the data in the table need not be obviously categorized and can easily recognized without having a particular table shades. One such scenario is when you only have 1 to 2 categories of data in table, there is no need to provide such distinction. However for multiple data sets, it would be efficient to present the data by grouping them by the color of the shade of their cell in the table.
N͟a͟t͟u͟r͟a͟l͟ d͟i͟s͟a͟s͟t͟e͟r͟s͟. Specifically, things such as hurricanes, earthquakes, and tsunamis.