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ludmilkaskok [199]
3 years ago
8

Can someone help please, this has been stressing me out

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
A. is 96
you would get 120+48+jk+li=360 and then you would get jk+il= 192 and divide that by 2
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The floor of a rectangular meeting room has a raised platform that is the same length as the room and is 1/6 the width of the ro
Vlad [161]

Step-by-step explanation:

Below is an attachment containing the solution.

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4 years ago
5(2 + x) + 2(6 - 2x) = 20
Jlenok [28]
I just distributed the 5 and 2 to the parentheses and the used PEMDAS

8 0
3 years ago
-2(bx - 5) = 16<br><br> What’s does b and x equal?
horrorfan [7]
To solve this problem you must apply the proccedure shown below:
 You have the following equation given in the problem above:
 <span>-2(bx - 5) = 16
</span> When you solve for bx, you have:
 <span>-2(bx - 5) = 16
 -2bx-10=16
 -2bx=26
 bx=26/-2
 bx=-13

 When you solve for b, you obtain:
 </span><span>-2(bx - 5) = 16
 -2bx=26
 b=-(26/2x)

 When yoo solve for x:
 </span>2bx=26
 x=-(26/2b)<span>

 </span>
3 0
3 years ago
What's 3x + 10 - x + 12
Zinaida [17]
2x+22 is the answer.
5 0
3 years ago
Read 2 more answers
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution
ankoles [38]

Answer:

a) Normal Distribution

b) 0.146

c) 0.070

Step-by-step explanation:

We are given the following information in the question:

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4

a) \bar{x}: mean number of accidents per week at the intersection during a year (52 weeks)

According to central limit theorem, as the sample size becomes larger, the distribution of mean approaches a normal distribution.

Since we have a large sample, the approximate distribution of \bar{x} is a normal distribution with

\text{Mean} = 2.2\\\text{Standard Deviation} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.4}{\sqrt{52}} = 0.19

b) P(mean is less than 2)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(x > 610)

P( \bar{x} < 2) = P( z < \displaystyle\frac{2 - 2.2}{0.19}) = P(z < -1.052)

Calculation the value from standard normal z table, we have,  

P(\bar{x} < 2) = 0.146

c) P(fewer than 100 accidents at the intersection in a year)

P(x < 100)

P( \bar{x} < \frac{100}{52}) =P(\bar{x} < 1.92) =P(z < \displaystyle\frac{1.92 - 2.2}{0.19}) = P(z < -1.473)

Calculation the value from standard normal z table, we have,  

P(x

7 0
3 years ago
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