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Alex787 [66]
2 years ago
6

How many would juile see?

Mathematics
2 answers:
Allisa [31]2 years ago
8 0

Answer:

<h2><u><em>12</em></u></h2>

Step-by-step explanation:

4*4*__=48

16*__=48

48/16=3

3*4=12

otez555 [7]2 years ago
6 0

Answer:

12 boxes on the right side

Step-by-step explanation:

4 going across and 3 rows so 12 boxes

48 divided by 3 is 16 but divided by 4 is 12

since there are 16 boxes at the top its a good inference that there's

only 3 flat rows meaning per every flat there would be 4 boxes and 3 rows

there would be 12 boxes on the right side.

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What is a35 for the arithmetic sequence presented in the table below?
Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

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