Given:
The measurement of the angles of a triangle are 3b,2b,and 4b.
To find:
The smallest angle.
Solution:
According to the angle sum property, the sum of all angles of a triangle is 180 degrees.
[Angle sum property]
Divide both sides by 9.
Now,
Therefore, the smallest angle is 40 degrees.
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Answer:
you currently have the value of x × 7, you need to divide it by 7 to find the value of x.
42 ÷ 7 = 6
Step-by-step explanation:
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
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