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oee [108]
3 years ago
7

What is the solution set to the given inequality? 6(x-2) 2 8 + 8x

Mathematics
1 answer:
avanturin [10]3 years ago
7 0

Answer:

48 x 2 − 184 x + 192

Step-by-step explanation:

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The cost of the fruit is given by the function y= 3x+1, where x is the number of fruits and y is the total cost. Find the
Elza [17]

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The answer is the second option: {4, 7, 10...}

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Graph the inequality.<br> 1
Mrrafil [7]

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Step-by-step explanation:

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3 years ago
Simplify: -1/2(6n+4) +2n - 5
Maurinko [17]

Answer:

Step-by-step explanation:

\frac{-1}{2}(6n+4)+2n-5 \\\\\frac{-1}{2}2(3n+2)+2n-5\\ -(3n+2)+2n-5\\-3n-2+2n-5\\-n-7

5 0
3 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
The cost of renting a table at the flea market is based on a fixed price per day plus an initial registration fee. If it costs $
Simora [160]

Answer:

c = 15d + 30

Step-by-step explanation:

Hey there!

This can be represented by an equation of a line, where the number of days is our x-values(d), and the price is our y-values(c).

The price for one day ($45) and the price for 4 days($90) are specific points on that line.

The points are (1, 45) and (4, 90).

We can first find the slope of the line:

  • As the price rises 45, the days increase by 3
  • Slope = rise/run
  • Slope = 45/3
  • Slope = 15

Now we can find the base price, by plugging the slope and a point into the equation y = mx + b.

Solve for b:

  • y = mx + b
  • 45 = 15(1) + b
  • 45 = 15 + b
  • 30 = b

The base price (b) is 30.

The equation is \text{\boxed{c = 15d + 30}}

6 0
2 years ago
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