Answer:
a) For a constant increment in x-variable, there is a constant increment in y-variable, for example, for x = 0 to x = 0.5 (increment = 0.5) y-variable goes from 60 to 62 (increment = 2); the same is valid for any couple of (x,y) values. This behaviour is characteristic of linear equations.
b) slope:
m = (increment in y-variable)/(increment in x-variable) = 2/0.5 = 4
y-intercept:
y1 = m*x1 + h
60 = 4*0 + h
60 = h
equation: y = 4x + 60
where y represents scores and x represents hours spent studying
c) The slope indicates that you need to study 1 hour to increase your score in 4 points
The y-intercept indicates that you will get at least a score of 60, even though you hadn't studied
Let us assume that the small no. is x.
So the larger no. is 16+x
so x+16+x=68
2x+16=68
2x=68-16
2x=52
X= 52/2 = 26
The small number is 26
The larger no. = 16 + 26
The larger no. Is 42
To find value of y in times o x we have to transfrom this equation.
LEts do this
x-0.25y=1.5 /-x subtract x both sides
-0.25y=1.5-x /*4 multiply by 4 both sides
-0.25y*4=4(1.5-x)
-1y=6-4x /*-1 multiply both sides by -1
y=4x-6
Answer:
Hence the corresponding equation of the given problem will be:
y'=|x-5|-1
Step-by-step explanation:
Let y' denote the corresponding equation after the translation of the given function y
We are given a equation of a function as: y=|x|.
Now we have to write an equation such that there is a translation 1 unit down and 5 units right of y=|x|.
We know that for any function f(x) the translation 'a' units down is given by:
f(x)-a
And the translation 'b' units right of a function g(x) is given by:
g(x-b)
Hence the corresponding equation of the given problem will be:
y'=|x-5|-1
+20 because when u deposit your adding money
