Find the percent increase. Round to the nearest percent

The functions f(x) and g(x) are shown on the graph.

goldfiish [28.3K]

Answer:Soo really I could give a fucif u believe me or not but the answer is d

Step-by-step explanation:

Jj

7 0

2 years ago

You wish to make an

Leokris [45]

Using the interest formulas, it is found that the values of the investment are given as follows:

Using simple interest, the value will be of $34,000.

Using compound interest, the value will be of $144,461.

Using continuous compounding, the value will be of $148,002.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

$A(t) = P(1 + rt)$

In which:

P is the initial amount.

r is the interest rate, as a decimal.

In this problem, we have that the parameters are as follows:

P = 9000, r = 0.07, t = 40.

Hence:

$A(t) = 9000(1 + 0.07 x 40) = 34200$

<h3>Compound interest</h3>

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

n is the number of compounding, for quarterly n = 4, then:

$A(t) = 9000\left(1 + \frac{0.07}{4}\right)^{4 \times 40}$

$A(t) = 144461$

<h3>Continuous compounding</h3>

$A(t) = Pe^{rt}$

Hence:

$A(t) = 9000e^{0.07 \times 40} = 148002$

More can be learned about the interest formulas at brainly.com/question/25296782

#SPJ1

7 0

1 year ago

PLEASE HELP MEE (40 points) will Mark BRAINLIEST!

Lady_Fox [76]

Need more information on the choice, please provide

4 0

2 years ago

A survey of 32 different gas stations in Texas found the average price of gasoline to be $3.19 a gallon with a sample standard d

Leni [432]

Answer:

The value of test statistic is -4.1247

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $3.26 a gallon

Sample mean, $\bar{x}$ = $3.19 a gallon

Sample size, n = 32

Sample standard deviation, σ = $0.096

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 3.26\text{ dollars a gallon}\\H_A: \mu < 3.26\text{ dollars a gallon}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{3.19 - 3.26}{\frac{0.096}{\sqrt{32}} } = -4.1247$

Thus, the value of test statistic is -4.1247

3 0

2 years ago

Heights for women are bell-shaped with a mean of 65 inches and standard deviation of 2.5 inches. If a random sample of 16 women

loris [4]

Answer:

μ= 65 inches; σ= 0.625 inch

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 65, \sigma = 2.5$

By the central limit theorem, the sample of 16 will have:

$\mu = 65, \sigma = \frac{2.5}{\sqrt{16}} = 0.625$

So the correct answer is:

μ= 65 inches; σ= 0.625 inch

8 0

2 years ago