Answer:
3xz5+2x+4y−2z
Step-by-step explanation:
2x−5y+3z5x+9y−2z
=2x+−5y+3xz5+9y+−2z
Combine Like Terms:
=2x+−5y+3xz5+9y+−2z
=(3xz5)+(2x)+(−5y+9y)+(−2z)
=3xz5+2x+4y+−2z
Answer:
(3, -6)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 4x - 18
y = -5x + 9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [2nd Equation]: 4x - 18 = -5x + 9
- [Addition Property of Equality] Add 5x on both sides: 9x - 18 = 9
- [Addition Property of Equality] Add 18 on both sides: 9x = 27
- [Division Property of Equality] Divide 9 on both sides: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [1st Equation]: y = 4(3) - 18
- Multiply: y = 12 - 18
- Subtract: y = -6
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
Your trying to move -8p to the right side , so first add 12 to 14 the -12 + 12 is zero and add 12 to plus then it would end up to -8p=5p+ whatever your number is the you look for p
Let the number of cards Aaron has : A
Given :
⊕ Bonny has twice as many cards as Aaron
⊕ Connor has 6 cards more than Bonny
⊕ Total cards : 101
⇒ Number of cards Bonny has : 2A
⇒ Number of cards Connor has : 2A + 6
⇒ Aaron cards + Bonny cards + Connor cards = 101
⇒ A + 2A + 2A + 6 = 101
⇒ 5A = 101 - 6
⇒ 5A = 95
⇒ A = 19
<u>Answer</u> : Aaron has 19 Cards
