How many ways can two names be chosen from 76 in a raffle if only one entry per person is allowed

The length of a rectangle is 8cm and the height is 16cm find the answer of the above figures using this formular...

notsponge [240]

Length=8cm
Breadth=16cm(Height)

<h3>Perimeter:-</h3>

$\\ \sf\longmapsto Perimeter=2(L+B)$

$\\ \sf\longmapsto Perimeter=2(16+8)$

$\\ \sf\longmapsto Perimeter=2(24)$

$\\ \sf\longmapsto Perimeter=48cm$

Area:-

$\\ \sf\longmapsto Area=Length\times Breadth$

$\\ \sf\longmapsto Area=8(16)$

$\\ \sf\longmapsto Area=128cm^2$

3 0

3 years ago

Find the area of the parallelogram with vertices:________.

marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0

3 years ago

Please help a girl outtttt

jeyben [28]

Answer:

bottom of graph will move from (0,0) to point (1,3) after transformation

Step-by-step explanation:

given

original : f(x) = $x^{2}$

transformed; g(x) = $(x-1)^{2}$ + 3

look at this way g(x) = $(x-h)^{2}$ + k

if (x-h), h>0, move h units to the right

if k>0, move k units up

the bottom of the graph will be at point (1,3)

3 0

3 years ago

A particle moves so that r(t) = ati + b sin atj. Show that the magnitude of the acceleration of the particle is proportional to

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Given

Position of particle is $r(t)=at\hat{i}+b\sin (at)\hat{j}$

i.e. distance from x axis is $b\sin (at)---1$

Distance from y axis at

velocity is given by $v=\frac{\mathrm{d} r}{\mathrm{d} t}$

$v=a\hat{i}+ba\cos (at)\hat{j}$

Similarly acceleration is given by

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=0\hat{i}-a^2b\sin (at)\hat{j}$

Magnitude of acceleration is $=\sqrt{(-a^2b\sin (at))^2}$

$=a^2b\sin (at)----2$

From 1 and 2 we can see that

Magnitude of acceleration is proportional to distance from x axis

$a\propto distance\ from\ x-axis$

5 0

3 years ago

Read 2 more answers

A painter rented a wallpaper steamer at 9am and returned it at 4pm he paid a total of 28.84 what was the total rental cost per h

Stolb23 [73]

9am to 4 pm is 7 hour and you use the total cost divid by hours you can get you answer which is 4.12 per hour

3 0

3 years ago