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dusya [7]
3 years ago
15

The radius of a circle is 1 foot. What is the area of a sector bounded by a 90 degree arc?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

The answer is 11/14 ft^2 or pi/4 ft^2

Step-by-step explanation:

The area of the sector bounded by that angle measure will be the area of the circle divided by 4

Area of the circle is;

pi * r^2

so the area here is;

22/7 * 1 * 1 = 22/7

divide this by 4

= 22/28 = 11/14 ft^2

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Can someone please help me with this geometry homework?
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The distances between the two points, in units, are given as follows:

7. \sqrt{2}

8. 2\sqrt{17}

9. 3\sqrt{2}

10. 3\sqrt{5}

The midpoints are given as follows:

11. (7,-4.5).

12. (2,4).

13. (7,0.5).

14. (5.5,-1.5).

<h3>What is the distance between two points?</h3>

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For item 7, the points are (-3,-2) and (-4,-3), hence the distance is:

D = \sqrt{(-4 + 3)^2 + (-3 + 2)^2} = \sqrt{2}

For item 8, the points are (-3,1) and (5,3), hence the distance is:

D = \sqrt{(5 + 3)^2 + (3 - 1)^2} = \sqrt{68} = 2\sqrt{17}

For item 9, the points are (-3,0) and (0,-3), hence the distance is:

D = \sqrt{(0 + 3)^2 + (-3 - 0)^2} = \sqrt{18} = 3\sqrt{2}

For item 10, the points are (1,-2) and (4,4), hence the distance is:

D = \sqrt{(4 - 1)^2 + (4 + 2)^2} = \sqrt{45} = 3\sqrt{5}

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence, for item 11, the midpoint is given by:

[0.5(9 + 5), 0.5(1-10)] = (7,-4.5).

For item 12, the midpoint is given by:

[0.5(-5 + 9), 0.5(7 + 1)] = (2,4).

For item 13, the midpoint is given by:

[0.5(9 + 5), 0.5(9 - 8)] = (7,0.5).

For item 14, the midpoint is given by:

[0.5(10 + 1), 0.5(4 - 7)] = (5.5,-1.5).

More can be learned about the distance between two points at brainly.com/question/18345417

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What can you add to 30 to make 50?
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