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masya89 [10]
3 years ago
11

A heron is perched in a tree 50 feet above sea level. Directly below the heron, a pelican is flying 17 feet above sea level. Dir

ectly below the birds is a trout, swimming 23 feet below sea level.
A.What’s the difference in height between the pelican and the heron?
B.What’s the distance in height between the pelican.
C.what’s the difference in height between the pelican and the trout.
D.What’s the distance in height between the pelican and the trout.
Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

Step-by-step explanation:

Your answer

A = 73

B= 33

C = 40

D = 40

Mark it as Brainlist answer. Follow me.

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(2, -1)

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because that's where the lines intersect

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Sue has $2.10 in dimes and nickels. If she has 12 more dimes than nickels, how many of each coin does she have?
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Sue would have 21 dimes and 12 less of 21 is 9, so sue has 9 nickels

dimes: 21
nickels: 9
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Separate 53 people into two groups so that the first group has 7 fewer than 4 times the number of people in the second group.
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In a church wing with 8 men and 10 women members find the probability that a 5 member committee chosen randomly will have.......
Sergeeva-Olga [200]

Answer:

a) Probability that a 5 member committee will have all men = 0.0065

b) probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

Step-by-step explanation:

Number of men = 8

Number of women = 10

Total number of members = 10 + 8 = 18

Probability = (Number of possible outcomes)/(Total number of outcomes)

Number of ways of selecting a 5 member committee from 18 people = ^{18}C_5 = \frac{18!}{(18-5)!5!} = \frac{18!}{13!5!} = 8568 ways

a) Probability that a 5 member committee will have all men

Number of ways of selecting 5 men from 8 men

= ^8C_5 = \frac{8!}{(8-5)!5!} = \frac{8!}{3!5!} = 56 ways

Probability that a 5 member committee will have all men = 56/8568

Probability that a 5 member committee will have all men = 0.0065

b)probability that a 5 member committee chosen randomly will have 3men and 2 women​

Number of ways of selecting 3 men from 8 men

=  ^8C_3 = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = 56 ways

Number of ways of selecting 2 women from 10 men

=  ^{10}C_2 = \frac{10!}{(10-2)!2!} = \frac{10!}{8!2!} = 45 ways

Number of ways of selecting 3 men and 2 women = 56*45

Number of ways of selecting 3 men and 2 women = 2520

Probability of selecting 3 men and 2 women = 2520/8568 = 0.294

probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

6 0
3 years ago
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