The constant variation k is 12
<span>this polynomial has a repeated factor in (x - 2). so its true</span>
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
-3x + 6 = 18...subtract 6 from both sides
-3x = 18 - 6
-3x = 12...divide both sides by -3
x = -12/3 reduces to -4 <===
Answer:
B. F(x) =X-4/11
Step-by-step explanation:
We are given the inverse function;
f^(-1)(x) = x + 4/11
Thus means, x was replaced with y and vise versa. Thus;
x = y + 4/11
Lets make y the subject;
y = x - 4/11
Thus,in inverse of a function we replace y with f(x) for the original function or f^(1)(x) for the inverse.
Thus, putting f(x) for y gives;
f(x) = x - 4/11
