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Rasek [7]
3 years ago
9

A restaurant has one price for adults and another price for children to eat at its buffet. Two families ate at the buffet. The T

raymore family has two adults and three children and their bill was $49.50. The Willis family has three adults and one child and their bill was $44.50. What is the cost for an adult to eat at the buffet and what is the cost of a child to eat at the buffet?
Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0
It costs an adult $12 and a child $8.50 to eat at the buffet.

2a+3c=49.40
3a+1c=44.50

c=44.50-3a

2a+3(44.50-3a)=49.50
-7a+133.5=49.50
a=12

2(12)+3c=49.50
3c=25.50
c=8.50
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Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

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Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
3 years ago
In the diagram below, NO is parallel to K L. If KN = 7, NO = 10, and
Vesnalui [34]
<h3>Answer:  14</h3>

=====================================================

Work Shown:

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Side note: The triangles are similar, which allows us to set up the proportion in step 1.

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Answer:

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