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3 years ago

BRAINLIEST TO BEST ANSWER :D

Mathematics

2 answers:

Temka [501]3 years ago

7 0

Answer:

Step-by-step explanation:

Liula [17]3 years ago

6 0

Answer:hope this helps!!! :)

defenitly A it equals x-6 not x-3

3(x - 6) + (4x + 12) - 6x => − 6

Step-by-step explanation:

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What is the solution to the system of equations?

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(-19,55) x is equal to -19 and y is equal to 55

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The sides of a rectangle are enlarged by a scale factor of 2. Write

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

both sides are multiplied by 2 which means its the original area*2*2 which means it's the original area*4

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Y=6x+5 is the equation. what is its gradient

Irina18 [472]

Gradient is synonymous to slope.

y = 6x + 5 is an example of a slope-intercept form of a straight-line equationl.

The slope-intercept equation is like this:

y = mx + b

where : m = slope ; b = "y-intercept"

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3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

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Answer:

Step-by-step explanation:

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