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4 years ago

Angle 1 and 2 are supplementary. Angle 1=3x° angle 2=(2x. -25)° select from the drop down menu

Mathematics

1 answer:

goldfiish [28.3K]4 years ago

8 0

Answer:

x = 41°

∠1 = 123°

∠2 = 57°

Step-by-step explanation:

If angles 1 & 2 are supplementary, that means...

$\angle1 +\angle2=180\textdegree$

To find the value of each angle, you first must find the value of x by plugging in the values of both angles...

$\angle1 +\angle2=180\textdegree\Longrightarrow3x+(2x - 25) = 180\textdegree$

First, combine like values, then subtract add 25 to both sides.

$3x + 2x = 5x\Longrightarrow 5x - 25+ (25) = 180 + (25)\\\\5x=205$

Then, divide both sides by 5, and plug the value of x into the original equations for angles 1 & 2.

$\frac{5x = 205}{5}\\\\x = 41\textdegree\\\\\angle1= 3x = 3(41) = 123\textdegree\\\\\angle2=2x-25=2(41)-25=82-25=57\textdegree$

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Show work and answer .............

Lelechka [254]

Answer:

1. 5

2. 5

3. -3

4.y= -1

5. 5

Step-by-step explanation:

1.)x- 2y= -25 ; y=3x

x-2(3x)=(-25)

x-6x=(-25) ; -5x=(-25) ; x=5

2.) 5x+3y =40; x=y

8y=40; y=5

3.) 4x-3y= -27; x=3y

4(3y)-3y= -27; 12y-3y=-27; 9y=-27; y=-3

4.)x-y=9; x=-8y; -8y-y=9; -9y=9; y=-1

5.) 2x+2y=30; y=2x ; 2x+2(2x)=30; 6x=30; x=5

8 0

3 years ago

Sienna has $8 and is saving $3 per week. Jacob has $6 and is saving $4 per week. Which model represents the equation that can de

user100 [1]

Answer:

Model B

Step-by-step explanation:

Model B correctly displays sienna's and jacob's equations.

For sienna, the $8 can be represented as 8 unit blocks, which is displayed in model 2. The $3 per week can be represented as 3 x tiles, as shown in the picture, because it represents how many weeks.

For jacob, the model shows 6 unit blocks which represents his 6 dollars. The $4 per week is represented with the 4 x tiles, and we use x tiles because we are calculating how many weeks.

4 0

4 years ago

Read 2 more answers

I need help on this qustion

erastova [34]

what I put into my basic calculator is 5(3/4)-6(1/8)= 3 ft

3 0

3 years ago

Please help and explain

Vikki [24]

Try this solution/explanation:
1. the rule is: m∠TRP=m∠YTR.
2. using the rule described above, it is possible to write the following equation: 3x=2x+35; ⇒ x=35°

Answer: 35°

5 0

3 years ago

The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 per

enot [183]

Answer:

The summer interval is wider and has a greater point of estimate

Step-by-step explanation:

Assuming this problem: "An environmental group wanted to estimate the proportion of fresh produce sales indentified as organic in a grocery store. In the winter, the group obtained a random sample of sales from the store and used the data to construct a 95percent z-interval for a proportion (0.087,0.133). Six months later in the summer, the group obtained a second random sample of sales from the store. The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 percent z-interval for a proportion constructed from the summer sample compare to the winter interval? "

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

We can find the margin of error from the interval given on this case would be:

$ME= \frac{0.133-0.087}{2}=0.023$

And the point of estimate for the proportion obtained would be:

$\hat p = 0.133-0.023=0.11$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =0.023$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.11(1-0.11)}{(\frac{0.023}{1.96})^2}=710.95$

And rounded up we have that n=711

Now we know that we use the same sample size for the new confidence interval. And replacing into the confidence interval formula we got:

$0.4 - 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.364$

$0.4 + 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.436$

And the new 95% confidence interval would be given (0.364;0.436) has a width of 0.436-0.364=0.072. And the width for the previous confidence interval is 0.133-0.087= 0.046. So then the best answer is:

The summer interval is wider and has a greater point of estimate

7 0

3 years ago