Angle 1 and 2 are supplementary. Angle 1=3x° angle 2=(2x. -25)° select from the drop down menu
1 answer:
Answer:
x = 41°
∠1 = 123°
∠2 = 57°
Step-by-step explanation:
If angles 1 & 2 are supplementary, that means...
To find the value of each angle, you first must find the value of x by plugging in the values of both angles...
First, combine like values, then subtract add 25 to both sides.
Then, divide both sides by 5, and plug the value of x into the original equations for angles 1 & 2.
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Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)