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rodikova [14]
3 years ago
15

2y–3x >10, how do u answer and graph that

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

slope=3/2 y inter. = (0,5)

Step-by-step explanation:

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A 35 foot tall pole is leaning against a building the angle it makes with the ground is 80° how tall is the wall
Eddi Din [679]
50 foot long is the wall
4 0
2 years ago
Find the sum of the first 12 terms of the sequence. Show all work for full credit.
ehidna [41]
The difference between each term is -5, i.e. we know one of our terms is -5n. Now we just need to adjust it to get u1 correct. At n=1, -5n would give us -5 therefore we need to add 6 to get to 1. This gives us our equation:

\boxed{u_n=-5n+6}

Now we can work out the sum easily (we can use an equation using the above but personally I prefer the other one as it's less prone to mistakes):
S_n= \frac{n}{2}(2u_1+(n-1)d)
We know n is 12, and we know u1 is 1, and we also know the difference is -5.

Substituting this in:
S_{12}= \frac{12}{2}(2*1+(12-1)*-5)=6(2-55)=6*-53 \\ \boxed{S_{12}=-318}
5 0
4 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
What's the estimate of 189,729
Elenna [48]
It's might be.....180,000 I'm sure
6 0
3 years ago
Read 2 more answers
Help with question 3 please
mel-nik [20]
Score = 6x+y

so 6x+y = xy
⇒ 6x = xy-y
⇒ 6x = y(x-1)
⇒ y = 6x/(x-1)

for x=0, y=0
x=1 , not possible
x=2, y = 12
x = 3, y = 9
x = 4, y = 8
x = 5, y = 7.5 (not possible)
x = 6 , y = 7.1 (not possible)
x = 7, y = 7
x = 8, y = 6.85 (not possible)
x = 9, y = 6.75 (not possible)...

Only five scores are possible.


6 0
4 years ago
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