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amid [387]
2 years ago
10

Complete the following statement.

Mathematics
2 answers:
Elis [28]2 years ago
4 0

Answer:

56 adults and 35 children

sum the parts of the ratio 16 + 10 = 26

Divide 91 by 26 to find one part of the ratio

= 3.5 ← 1 part of the ratio

16 parts = 16 × 3.5 = 56 ← number of adults

10 parts = 10 × 3.5 = 35 ← number of children

Step-by-step explanation:

shusha [124]2 years ago
4 0

Answer:

56 adults and 35 children

Step-by-step explanation:

 

sum the parts of the ratio 16 + 10 = 26

Divide 91 by 26 to find one part of the ratio

91/26 = 3.5 ← 1 part of the ratio

16 parts = 16 × 3.5 = 56 ← number of adults

10 parts = 10 × 3.5 = 35 ← number of children

Therefore it 56 adults and 35 children.

To Check the Answer:  56 + 35 = 91

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In the △PQR, PQ = 39 in, PR = 17 in, and the altitude PN = 15 in. Find QR.
Licemer1 [7]

Answer:

So, this triangle PQR can be broken into two right triangles, PNQ and PNR, with legs PQ = 39, PN =15, and QN = ? and PR = 17, PN = 15, and NR =? respectively.


Let's solve for what is easier first:

Since we know that 5-15-17 is a Pythagorean triplet, we can infer that NR is 5....like I said earlier, it is a right triangle, so this guess holds true.


Here comes the interesting part:

Now, we have one part of QR, which is QN.

The other part can be solved by using the Pythagorean theorem.

It is (39^2-15^2)^(1/2)..which gives you 36, the square root of 1296, which happens to be the difference between the squares of 15 and 39.

SO, QR = QN + NR

5+36 = 41

QR = 41.

Hope this helps!

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4 years ago
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2 is subtracted from the square of a number
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3 years ago
What is 38 divied by 7 in long division
notsponge [240]

Answer: 5.43

Step-by-step explanation:

4 0
3 years ago
Please help me, i suck at this​
Svetradugi [14.3K]

Answer:

(5, -5)

General Formulas and Concepts:

<u>Pre-Algebra </u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • <u> </u>Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Coordinates (x, y)
  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

2x - 3y = 25

5x + 3y = 10

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine two equations:                                                                                  7x = 35
  2. [Division Property of Equality] Divide 7 on both sides:                                  x = 5

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em> [1st Equation]:                                                                           2(5) - 3y = 25
  2. Multiply:                                                                                                             10 - 3y = 25
  3. [Subtraction Property of Equality] Subtract 10 on both sides:                       -3y = 15
  4. [Division Property of Equality] Divide -3 on both sides:                                y = -5
5 0
3 years ago
Read 2 more answers
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