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uranmaximum [27]
2 years ago
5

A triangle has vertices on a coordinate grid at N (7,3), 0(-8, -3), and

Mathematics
1 answer:
Leokris [45]2 years ago
4 0

Answer:

d\approx 16.16\ units

Step-by-step explanation:

<u>Distance Between two Points in the Plane</u>

Given two points A(x,y) and B(w,z), the distance between them is:

d=\sqrt{(z-y)^2+(w-x)^2}

The triangle formed by the points N (7,3), 0(-8, -3), and  P(-8,-8) is shown in the image provided.

We are required to find the distance between N and O:

d=\sqrt{(-3-3)^2+(-8-7)^2}

d=\sqrt{(-6)^2+(-15)^2}

d=\sqrt{36+225}

d=\sqrt{261}

Since 261=9*29:

d=3\sqrt{29}

\mathbf{d\approx 16.16\ units}

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If x=7+root 40 ,find the value of root x+1by the root of x​
Luda [366]

Chapter : Algebra

Study : Math in Junior high school

x = 7 + √40

find √x of √x + 1

= √x + 1

= √(7+√40) + 1

in Formula is :

= √7+√40 = √x + √y

= (√7+√40)² = (√x + √y)²

= 7+√40 = x + 2√xy + y

= 7 + √40 = x + y + 2√xy

→ 7 = x + y → y = 7 - x ... Equation 1

→ √40 = 2√xy → √40 = 2.2√10 = 4√10

= xy = 10 ... Equation 2

substitution Equation 1 to 2 :

= xy = 10

= x(7-x) = 10

= 7x - x² = 10

= x² - 7x + 10 = 0

= (x - 5)(x - 2) = 0

= x = 5 or x = 2

Subsitution x = 5 and x = 2, to equation 1

#For x = 5

= y = 7 - x

= y = 7 - (5)

= y = 2

#For x = 2

= y = 7 - x

= y = 7 - (2)

= y = 5

and his x and y was find :

#Equation 1 :

= x = 5 and y = 2

#Equation 2 :

= x = 2 and y = 5

So that :

√7+√40 = √x + √y

= √7+√40 = √2 + √5

And that is answer of question :

= √2 + √5 + 1

3 0
3 years ago
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