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3 years ago

14

A builder is buying property where she can build new houses the line plot shows the size of the lights for each house which is t

he average size of the lots

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

Step-by-step explanation:

13,000

arlik [135]3 years ago

6 0

Answer:

TBH IDRK

Step-by-step explanation:

You do what ever ask ur teacher not me im on here looking for answers myself lmbo

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What is the solution 4x+1y ≤48 and 10 ≤y ?

PIT_PIT [208]

The answer is X=19/2 y=10

6 0

3 years ago

Which ordered pair is a solution of the inequality? y is greater than or equal to 4x-5

lesya692 [45]

(1,1) -->> 1 >= 4(1) - 5 -->> 1 >= 4-5 -->> 4 >= -1

8 0

3 years ago

A store ordered 28 boxes holding 12 banana muffins each and five boxes holding 6 blueberry muffins each. What was the total numb

sveticcg [70]

Answer:

366 muffins

Step-by-step explanation:

28 x 12 = 336

5 x 6 = 30

336 + 30= 366 muffins

6 0

3 years ago

MATH!!! 15 points ;)) find the volume of the composite figure

andrezito [222]

Answer:

(2*2*1.5*1/3)+(2*1.5*4)= 14

Step-by-step explanation:

To find the area of a pyramid, you use the equation of 1/3 *lwh. When we place the values in there, we get 2*2*1.5*1/3, which is equal to 2. Then we solve the bottom part. Since it is a rectangular prism, we use the equation of lwh. When we insert the values, we get 2*1.5*4, which is equal to 12. Now, we take these two values of 2 and 12 and we combine them, giving us our final answer of 14.

8 0

1 year ago

Please help!!!! will mark brainlest

fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

Area of rectangle=50 in²

Next, calculate the area of the trapezoid:

Area of trapezoid= $\frac{h(b_{1} +b_{2}) }{2}$

h=10 in-6 in

h=4 in

$b_{1} =15 in$

$b_{2} =15 in-5 in$

$b_{2} =10 in$

Area of trapezoid= $\frac{4in(7 in+10in)}{2}$

Area of trapezoid= $\frac{4(17in^{2}) }{2}$

Area of trapezoid= $\frac{68in^{2} }{2}$

Area of trapezoid= $34in^{2}$

Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²

3 0

2 years ago