Mass of CO₂ = 33 g
<h3>Further explanation </h3>
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Reaction
CH₄ + 2O₂⇒CO₂ + 2H₂O
mol CH₄ :
mol O₂ :
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients
Because O₂ ratio smaller then O₂ becomes the limiting reactants
So mol CO₂ from limiting reactants
mol CO₂ :
mass CO₂ :
Answer:
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Answer:
CaCO3----------CaO+CO2
(40g+12g+16g×3) of CaCO3 produce (40g+16g) of CaO
100g of CaCO3 -----------------56g of CaO
20g of CaCO3-------------------x grams of CaO
x=(20g×56g)÷100g
x=1120gg÷100g
x=11.2g of CaO
Therefore, 11.2grams of CaO from 20grams of CaCO3
HOPE IT HELPED, PLEASE MARK BRAINLIEST
Answer is: <span>the pressure of the gas is 9,2 atm.
</span>p₁ = 4,0 atm.
T₁ = 300 K.
V₁ = 5,5 L.
p₂ = ?
T₂ = 250 K.
V₂ = 2,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of its Kelvin temperature and its pressure.<span>
</span>p₁V₁/T₁ = p₂V₂/T₂.
4 atm · 5,5 L ÷ 300 K = p₂ · 2,0 L ÷ 250 K.
0,0733 = 0,008p₂.
p₂ = 9,2 atm.
You have to use the combined gas law (P₁V₁/T₁=P₂V₂/T₂) and solve for P₂ to get P₂=P₁V₁T₂/T₁V₂.
You need to convert all of the temperature values into terms of Kelvin so -50°C turns into 223K and 102°C turns to 375K. After you make that conversion you can just plug in all of the values into the idea gas law and you should get P₂=228.5kpa.
I hope this helps. Let me know if anything is unclear.
