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The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.
The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.
The specific heat has been expressed as:
The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.
The given mass of calorimeter has been,
The specific heat of the calorimeter has been,
The change in temperature of the calorimeter has been,
Substituting the values for heat released:
The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.
Learn more about specific heat, here:
Answer:- molar mass of the unknown gas is 71.5 gram per mol.
Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.
When we compare the effusion rates of two gases then the formula for Graham's law is:
In this formula, V stands for volume and M stands for molar mass
Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:
let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.
Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:
doing squares to both sides:
So, the molar mass of the unknown gas is 71.5 grams per mol.