86 percent is the percent yield for this experiment if he expected to produce 5g of product.
Explanation:
Given that:
mass of test tube = 5 grams
mass of test tube + reactant is 12.5 grams
mass of reactant = ( mass of test tube + reactant ) - (mass of test tube)
mass of reactant = 12.5 -5
= 7.5 grams
when 7.5 grams of reactant is heated mass of test tube was found to be 9.3 grams.
so mass of product formed = 9.3 - 5
= 4. 3 grams of product is formed (actual yield)
However, he expected the product to be 5 grams (theoretical yield)
Percent yield =
x 100
putting the values in the formula:
percent yield =
x 100
= 86 %
86 percent is the percent yield.
<u>Answer:</u> The ionic compound formed is
(barium fluoride)
<u>Explanation:</u>
Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.
Taking the metal as barium and non-metal as fluorine.
Barium is the 56th element of the periodic table having electronic configuration of ![[Xe]6s^2](https://tex.z-dn.net/?f=%5BXe%5D6s%5E2)
This element will loose 2 electrons and will form
ion
Fluorine is the 9th element of the periodic table having electronic configuration of ![[He]2s^22p^5](https://tex.z-dn.net/?f=%5BHe%5D2s%5E22p%5E5)
This element will gain 1 electron and will form
ion
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Hence, the ionic compound formed is
(barium fluoride)
Answer:
C3H3O3
Explanation:
To find its molecular formula, we simply use the empirical formula together with the molar mass. Firstly, we obtain the molar mass of the empirical formula CHO. His can be obtained by using the masses of the individual atoms. The masses are 12, 1 and 16 for carbon, hydrogen and oxygen respectively.
Hence: (12+[6+1)n = 88.12
29n = 88.12
n = 3
The molecular formula is thus C3H3O3
Answer:
The silver carbonate would be or would act as a base, while the strong acid that we would choose is hydrochloric acid (HCl), these two will suffer a chemical reaction when they interact ...
As for the tables, none are visualized, so the question is considered incomplete.
Ag2CO₃ + 2HCl (diluted) → AgCl + CO₂ ↑ + H₂O
Explanation:
Silver carbonate is considered a tertiary salt. Which these salts have three components, one is a metal, another is a carbon and the other an oxygen ...
When related to an acid, they act as a base forming an acid-base conjugation.