Answer:
Please Find the solution below
Step-by-step explanation:
Let us say the two equations are
x+y=5 --------------(A)
x-y=1 -------------(B)
Let us solve them for x and y by adding them
2x=6
x=3
Hence from (A)
3+y=5
y=2
Hence our solution is
x=3, y=2
Adding same number to equation (A) say 2 we get
x+y+2=5+2
x+y=5+2-2
x+y=5
Hence equation remains the same while adding same number to each side.
Same thing happens if we add same number to equation (B)
Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.
Answer : 
Given expression is 
To make perfect square trinominal we use completing the square method
In completing the square method we add and subtract the half of square of coefficient of middle term
Here coefficient of middle term is -7
Half of -7 is 
Square of is 
=
So the expression becomes ![x^2 - 7x + [tex] \frac{49}{4}](https://tex.z-dn.net/?f=%20%20x%5E2%20-%207x%20%2B%20%20%5Btex%5D%20%5Cfrac%7B49%7D%7B4%7D%20%20)
that gives perfect square trinomial
Hence , the value of 'c' is
18m
Step-by-step explanation:
5x3=15 +3 =18
The area of the side walk would be 5.5ft^2. Hope this helps
Answer:
m∠RQS = 72°
m∠TQS = 83°
Step-by-step explanation:
m∠RQS +m ∠TQS = m∠RQT
The two angles combine to make a larger angle
So
m∠RQS = (4x - 20)
m∠TQS = (3x + 14)
(4x - 20) + (3x + 14) = 155
Group the Xs and the constants
4x + 3x - 20 + 14 = 155
Combine like terms
7x - 6 = 155
Add 6 to both sides
7x = 161
Divide by 7 on both sides
x = 23
Check:
4(23) - 20 + 3(23) + 14 = 155
92 - 20 + 69 + 14 = 155
155 = 155
But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.
m∠RQS = 4(23) - 20 = 72°
m∠TQS = 3(23) + 14 = 83°
Checking:
72 + 83 = 155
