A building casts a shadow of 30ft.

Jerry's Seed Palace claims that 80% of its lima bean seeds will germinate. Suppose the company's claim is true. Callie buys a pa

Mekhanik [1.2K]

Answer:

A

Step-by-step explanation:

This is a Bernoulli trial problem.

Since the probability that the seed will germinate is 80% or 0.8, the probability that they won’t germinate is 0.2

Now let’s say the probability to germinate is p and the probability not to is a, we can now set up the Bernoulli equation in this regard. Since we are proposing that exactly 14 will germinate, it means 6 are not expected to germinate

P(14) = 20C14 (0.8)^14 (0.2)^6 = 0.109099700973

Option A is the right answer

3 0

2 years ago

I need help with number 3

Juli2301 [7.4K]

Answer:

a) 8 apples

b) 5 oranges

c) 2 oranges and 6 apples

Step-by-step explanation:

a) 8 apples × 1$ = 8$ < 10$

b) 5 oranges × 2$ = 10$

c) 2 oranges × 2$ = 4$

6 apples × 1$ = 6$ (4+6=10)

7 0

2 years ago

Read 2 more answers

Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an

Fantom [35]

9514 1404 393

Answer:

about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0

3 years ago

P(x) = 2x^3+5x -19 if x=2

AfilCa [17]

I think the answer is 2p = 7

7 0

2 years ago

F(x) = 2x^2 − 3x − 5 Part

riadik2000 [5.3K]

Answer: Answer is in the steps..

Step-by-step explanation:

f(x)= $2x^{2}$ - 3x -5

A) To find the x intercepts of a parabola we have to set the whole equation equal zero because the x intercept is when y equal zero in other words where f(x) equal zero.

$2x^{2}$ - 3x - 5 = 0 Now solve using quadratic formula.

x = -b± $\frac{\sqrt{b^2 -4ac } }{2a}$

x = 3 ± $\sqrt{9+40} /2a$

x = 3 ± $\sqrt{49}$ / 2a

x= 3 ± 7 /4

x= -1 or x = 5/2

The x intercepts are (5/2,0) and (-1,0)

B) The graph vertex of the graph of f(x) is going to be at a minimum because the leading coefficient of the function has a positive integer which means the parabola will open up and its vertex will be at the minimum point.

Using the x coordinates we could find their average and find the x coordinate of the vertex.

$\frac{5}{2} + -\frac{1}{1}$ = $\frac{3}{2} / \frac{2}{1}$ = 3/4

The x coordinate of the vertex is 3/4 so we will input that into the equation and solve for the y coordinate

$2(\frac{3}{4})^2 - 3 (\frac{3}{4}) - 5$ = 18/16 - 9/4 -5 = -49/8

The y coordinate of the vertex is -49/8

So the vertex is (3/4, -49/8)

C) First I will graph the vertex and then graph he two x intercepts and connect then like a U shape.

5 0

3 years ago