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e-lub [12.9K]
3 years ago
14

Please help with the following question

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0
P1=(0,0)=(x1,y1)→x1=0, y1=0
P2=(3,-2)=(x2,y2)→x2=3, y2=-2

Slope: m=(y2-y1)/(x2-x1)
m=(-2-0)/(3-0)
m=(-2)/3
m=-2/3

Point-slope equation:
y-y1=m(x-x1)
y-0=(-2/3)(x-0)
y=-(2/3)x

Answer: The equation of the line is: y=-(2/3)x
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Factor f(x)=4x²-15x-25 and then use zero-product property to find the zeros of the quadratic function. Show all work (Will Mark
Ostrovityanka [42]
<span>f(x)=4x²-15x-25
</span><span>f(x)=(4x + 5)(x - 5)

</span><span>zero-product property 
let </span>f(x)=(4x + 5)(x - 5) = 0
so
(4x + 5)(x - 5) = 0
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x - 5 =0
x = 5

answer
factor: (4x + 5)(x - 5)
x = 5 and x = -1.25

6 0
3 years ago
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