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3 years ago

I’m doing a percent equation I need help please here’s the question. Blank percent of 20 = 14

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

Answer:

x = 70

Step-by-step explanation:

x% 20 = 14

x / 100 * 20 = 14

x / 5 = 14

x = 14 * 5

ZanzabumX [31]3 years ago

3 0

100/20=5
14*5=70
Answer: 70%

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Step-by-step explanation:

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3 years ago

Find the value of y in the equation attached to this question

dlinn [17]

Answer:

y = 4

Step-by-step explanation:

1) Simplify $3^5$ to 243.

${9}^{y}=\frac{243\times {9}^{6}}{{27}^{3}}$

2) Simplify ${9}^{6}$ to 531441.

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3) Simplify $243\times 531441$ to 129140163.

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5) Simplify $\frac{129140163}{19683}$ to 6561.

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6) Convert both sides to the same base.

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7) Cancel the base of 9 on both sides.

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ROR

3 0

2 years ago

Read 2 more answers

Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf

Papessa [141]

The table is missing in the question. The table is provided here :

Group 1 Group 2

34.86 64.14 mean

21.99 20.46 standard deviation

7 7 n

Solution :

a). The IV or independent variable = Group 1

The DV or the dependent variable = Group 2

b).

$H_0: \mu_1 = \mu_2$

$H_a:\mu_1 < \mu_2$

Therefore, $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now, $df = min(n_1 - 1, n_2 - 1)$

df = 7 - 1

= 6

Therefore the value of p :

$=T.DIST(-2.579143,6,TRUE)$

= 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

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4 years ago

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Answer:

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