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3 years ago

Please help 6th grade math i will mark brainliest to 1 answer select all that are equivalent to 15%

Mathematics

2 answers:

Triss [41]3 years ago

7 0

Answer:

.15

Step-by-step explanation:

dimulka [17.4K]3 years ago

7 0

Answer:

.15, 3/20

Step-by-step explanation:

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A shipment of 40 fancy calculators contains 3 defective units. What is the probability if a college bookstore buys 20 calculator

JulsSmile [24]

Answer:

38.46%

Step-by-step explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

There are 40 calculators in one shipment, 37 of them good items and 3 of them are defect items. We need to choose 19 good calculators and 1 defect calculator. The number of ways to do that will be:

$\frac{37}{19}$ * $\frac{3}{1}$ = 37! $\frac{37!}{19!(37-19!)} * \frac{3!}{1!(3-1)!}$ = 53017895700

The number of possible ways to choose 20 calculators out of 40 calculators will be:

$\frac{40}{20}$ = $\frac{40!}{20!(40-20!)}$ =137846528820

The chance will be: 53017895700/ 137846528820 = 0.3846= 38.46%

4 0

3 years ago

HELP QUICKLY AND FAST PLS IM GIVING BRAINLIEST!!!

grigory [225]

Answer:

Step-by-step explanation:

3 0

3 years ago

Can you please help me solve this

Snezhnost [94]

Answer:

yes

Step-by-step explanation:

3 0

4 years ago

Write in simplest radical form: √208

Arte-miy333 [17]

$208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\Answer:\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a$

6 0

3 years ago

According to the "January theory," if the stock market is up for the month of January, it will be up for the year. If it is down

PSYCHO15rus [73]

Answer:

The required probability is 0.031918.

Step-by-step explanation:

Consider the provided information.

It is given that According to an article in The Wall Street Journal, this theory held for 22 out of the last 34 years.

Therefore n=34

The probability it is either up or down is 0.5.

Thus the value of p =0.5 and q = 0.5

Now calculate the probability

Let X is the number of years that theory held.

X has a binomial distribution with n=34 and p=0.5

$P(X=22)=\binom{34}{22}(0.5)^{22}(0.5)^{12}\\P(X=22)=\frac{34!}{22!\times 12!}(0.5)^{22}(0.5)^{12}\\P(X=22)=548354040\times 5.8207660913\times 10^{11}\\P(X=22)=0.0319184060208\\P(X=22)\approx0.031918$

Hence, the required probability is 0.031918.

8 0

3 years ago