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NemiM [27]
4 years ago
15

PLZ HELP. I WILL GIVE BRAINLIEST. 30 POINTS

Mathematics
1 answer:
luda_lava [24]4 years ago
4 0
Part A answer is 25/
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Rewrite the following expression 15+21 using the GCF and the distributive property
avanturin [10]
First, we want to find the GCF of 15 and 21, which is 3. Now we do 15 divided by 3 and 21 divided by 3, which gives us 5 and 7. To rewrite the expression, we take the GCF and put it on the outside of the parenthesis. Inside the parenthesis, we put 5 + 7. So it'll look like this:

3(5 + 7)
3 0
3 years ago
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Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12
BARSIC [14]

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}

\text{Mean age of players}=\frac{145}{12}=12.0833

Let us find median of data.

10,11,11,12,12,12,12,12,13,13,13,14        

\text{Median age of softball players}=\frac{12+12}{2}

\text{Median age of softball players}=\frac{24}{2}=12

We can see that average of our data is 12 years.    

Therefore, a measure of central tendency will be better choice to describe ages of softball players.      

7 0
3 years ago
Find the common ratio of the sequence 2,8,32,128..
Nezavi [6.7K]
4 because that is what's multiplied throughout
7 0
3 years ago
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Simplify: ^4square root 400/ ^4square root 5 show your work
Rainbow [258]
⁴√400 / ⁴√5 = 400^¼ / 5^¼
= (5 x 2²)² / 5^¼
= 5² x 2⁴ / 5^¼
= ⁴√5^7 x 2⁴
7 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assum
attashe74 [19]

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

 

At 95% confidence level, the value of z is equivalent to:

z = 1.96

 

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

 

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

6 0
3 years ago
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