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3 years ago

6

PLEASE HELP! I WILL GIVE BRAINLIEST!! Six less than the quotient of a number and 4 is 11. What is the number? Let n be the unkno

wn number

1 answer:

shutvik [7]3 years ago

5 0

Answer:

n/4-6

Step-by-step explanation:

n/4-6

This is the expression because we need to divide n by 4 and subtract 6

The number is 68

68 divided by 4= 17

17-6=11

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Angel believes that a vertical shift of the parent function f(x)=x^2 will always change the domain of the function do you agree

Nuetrik [128]

Disagree, A vertical shift always changes the domain of a function

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2 years ago

Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .

belka [17]

Answer:

Your friend sees you moving at 0.25 m/s upstream.

Step-by-step explanation:

Remember that relative velocity is the velocity of an object in relation to another object. In this example, your friend sees you moving with respect to the river with a relative velocity (Vr) of:

Vr = Yor Velocity (Vy) - The river Velocity (Vriver) =

Vr = 1.25 m/s - 1 m/s = 0.25 m/s

I hope my answer helped you.

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3 years ago

Jsca hsisde sjdncr dnaefa cdjerasfrecs

VikaD [51]

Answer:

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3 years ago

Which expressions are equivalent to the one below? Check all that apply. Log^7 1 * Log^5 25

Luda [366]

Answer:

B if you mean log_7 (1)*log_ 5 (25)

Step-by-step explanation:

I think you mean 7 and 5 as bases... like

log_7(1)*log_5(25)

log_7(1)=0 because 7^0=1

log_5(25)=2 because 5^2=25

So you have to perform the following operation 0*2=0

so 0 is definitely one answer

1 and 5*7 are definitely not equal to 0

let's look at last choice now

log_7(7)=1 because 7^1=7

so D is equivalent to saying 2*1 which is 2 not 0

so only one choice works and it is B

7 0

3 years ago

Iron deficiency anemia is an important nutritional health problem in the U.S. A dietary assessment was performed on 51 boys 9-11

Bond [772]

Answer:

a) Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

b) $t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

c) $12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

Step-by-step explanation:

Information given

$\bar X=12.50$ represent the mean for the daily iron intake

$s=4.75$ represent the sample deviation

$n=51$ sample size

$\mu_o =14.44$ represent the reference value

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Part a

We want to test if the mean iron intake among the low-income group is different from that of the general population, the system of hypothesis would be:

Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

Part b

Since we don't know the population deviation the statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got

$t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

Part c

The confidence interval would be given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

For the 95% confidence interval we can find the critical value in a t distribution with 50 degrees of freedom and we got:

$t_{\alpha/2}= 2.01$

And replacing we got:

$12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

7 0

4 years ago