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Mumz [18]
3 years ago
15

How do you find the original price of an item, given the tax percent and the final cost ?

Mathematics
1 answer:
olganol [36]3 years ago
8 0
Umm when you buy something and it gives you tax and you pay the hole thing with tax
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What is the volume of the cylinder below?
tatyana61 [14]

Answer:

I would go with the first one

Step-by-step explanation:

I put 4/3 x 3.14 x 6² on the calculator and it gave me 150.72 so A is the closest I'm not 100% sure but ye

5 0
3 years ago
3 times the difference between 4 twenty-fives and 3 twenty-fives
Wittaler [7]
The answer to that is 75
5 0
4 years ago
PLS HELP ASAP!!!
scoray [572]

Answer:

y>4x+1

Step-by-step explanation:

We got two simple steps for this question:

1.Find the equation(y=mx+b):

I want to test these two points on my formula:

(0, 1), (–1, –3)

m =  \frac{y2 - y1}{x2 - x1}  =   \frac{1 - ( - 3)}{0 - ( - 1)}  =  \frac{4}{1}  = 4

so we just calculated our m and now it time for b

y = 4x  +  b =  =  =  > 1 = 4(0) + b =  =  =  > b = 1

So your criterion is y=4x+1

2.

we are looking for ys greater than xs so your answer is gonna be y>4x+1

4 0
2 years ago
A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

8 0
4 years ago
Read 2 more answers
Q.Jason has 3 red pencils and 6 yellow pencils. Which statement is true?
igor_vitrenko [27]

Answer:

The number of red pencils is 2 times the number of yellow pencils

5 0
3 years ago
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