Answer:
Let's solve your system by elimination.
3x+4y=29;6x+5y=43
Multiply the first equation by -2,and multiply the second equation by 1.
−2(3x+4y=29)
1(6x+5y=43)
Becomes:
−6x−8y=−58
6x+5y=43
Add these equations to eliminate x:
−3y=−15
Then solve−3y=−15for y:
−3y=−15
−3y
−3
=
−15
−3
(Divide both sides by -3)
y=5
Now that we've found y let's plug it back in to solve for x.
Write down an original equation:
3x+4y=29
Substitute5foryin3x+4y=29:
3x+(4)(5)=29
3x+20=29(Simplify both sides of the equation)
3x+20+−20=29+−20(Add -20 to both sides)
3x=9
3x
3
=
9
3
(Divide both sides by 3)
x=3
Answer:
x=3 and y=5
Step-by-step explanation:
I love this stuff 229 999 0523
Answer:
7 
Step-by-step explanation:
2 
+ 5 
= 2+5=7, + =
= 7
To find the dimensions you can just factor the equation...
x^2+4x-21
x^2-3x+7x-21
x(x-3)+7(x-3)
(x+7)(x-3) and this is equal to LW or WL
And note that x>3 for any possible solution.
