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ICE Princess25 [194]

3 years ago

7

Quick 50 points A city will soon be voting on a bond issue which will provide the necessary funds for a new middle school. The s

chool board wants to know how likely it is that the bond issue will pass. They randomly sample three groups of 200 people and ask each person whether they are for or against the bond issue. The results are recorded in the table below. For Against Sample #1 111 89 Sample #2 97 103 Sample #3 104 96 Based on the collected data, do you think the bond issue will pass or fail? How confident are you? Explain your reasoning using complete sentences. Using the mean of the samples, approximately how many of the 15,000 voters would you expect to vote against the bond issue?

2 answers:

Black_prince [1.1K]3 years ago

8 0

Answer:

Stay Positive And You Will Find The Answer.

Step-by-step explanation:

r-ruslan [8.4K]3 years ago

4 0

Answer:

1. Pass, Very, Because there are 312 (pass) and 288 (fail), there is more Pass than Fail.

2. 7200 voters against the bond issue.

Don't cheat on school, whether it is hard or not.

I am only helping you because the 2nd one is a little tricky, but please try even harder next time.

Anyways I am most likely too late, lol.

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A coin bank for donations for the protection of the reef contained Php 1,570. There were twice as many Php 5-coins as

kvasek [131]

Answer:

There are 144 Php 5-coins, 72 Php 10-coins and 130 Php-1 coins

Step-by-step explanation:

The amount of the coins in the coin bank = Php 1,570

The number of Php 5-coins = 2 × The number of Php 10-coins

The number of Php 5 coins = The number of Php 1-coins + 14

Let 'x' represent the number of Php-5 coins, let 'y' represent the number of Php 10-coins, and let 'z' represent the number of Php 1-coins, we get;

x = 2 × y...(1)

x = z + 14...(2)

5·x + 10·y + z = 1,570...(3)

From equation (1) equation (2), and equation three, we have;

y = x/2

z = x - 14

5·x + 10·x/2 + x - 14 = 1,570

11·x - 14 = 1,570

x = (1,570 + 14)/11 = 144

The number of Php 5-coins, x = 144

y = x/2

∴ y = 144/2 = 72

The number of Php 10-coins, y = 72

z = x - 14

∴ z = 144 - 14 = 130

The number of Php 1-coins, z = 130

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Step-by-step explanation:

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Art [367]

Step-by-step explanation:

Okay, so...

The Median of a trapezoid is directly in the middle. For some weird mathimatical reason you won't ever need to know unless it's on an exam or you become a math major, its midsegment is the average of the top length and the bottom length.

In other words,

EF = ( BC + AD ) / 2

So for part 1, we can use that equation to find x.

$EF = ( BC + AD ) / 2$

Insert known equations.

$4x-18=[(x+12)+(3x-4)]/2$

Simplify within parentheses.

$4x-18=[x+12+3x-4]/2$

$4x-18=[x+3x+12-4]/2$

Add.

$4x-18=[4x+8]/2$

Divide.

$4x-18=2x+4$

Simplify.

$(4x-2x) +(-18+18)=(2x-2x)+(4+18)$

$2x=22$

Divide both sides by 2.

$x=11$

Part 2 is a lot easier now. All we have to do is plug in 11 for x.

$BC =x+12$

$BC = 11+12$

$BC = 23$

-

$AD = 4x-18$

$AD = 4(11)-18$

$AD = 44-18$

$AD = 26$

-

$EF = 3x-4$

$EF = 3(11)-4$

$EF = 33-4$

$EF = 29$

Answer:

Part I: x = 11

Part II:

BC = 23
AD = 26
EF = 29

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