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Mashcka [7]
3 years ago
10

A market sells 6 cans of food for every 7 boxes of food. The market sold a total of 26 cans and boxes today. How many

Mathematics
1 answer:
mamaluj [8]3 years ago
3 0
Option 2 is the correct answer
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Libby needs to cut pieces of oak molding that are 3/4 yard long. She has 2 yards of oak molding. How many pieces can she cut? Ho
jek_recluse [69]

Answer: She can make two 3/4 yards long of oak molding. She will have half of the second one left over.

Step-by-step explanation:

3 0
3 years ago
Of the 1000 students in a local college ,
dimaraw [331]
Can you please explain? Or maybe continue your question please?
5 0
2 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Given the recursive function f(n) = f(n - 1) - 3 ; f(1) = 9 , what would be the first three terms of the sequence ?
Ann [662]

The first three terms of sequence are 9 , 6 , 3

<em><u>Solution:</u></em>

Given the recursive function f(n) = f(n - 1) - 3

Where f(1) = 9

To find: First three terms of sequence

Substitute n = 2 , n = 3 and n = 4 in given recursive function

When n = 2

f(n) = f(n - 1) - 3

f(2) = f(2 - 1) - 3

f(2) = f(1) - 3

f(2) = 9 - 3 = 6

f(2) = 6

Thus second term is 6

When n = 3

f(3) = f( 3 - 1) - 3

f(3) = f(2) - 3

f(3) = 6 - 3 = 3

f(3) = 3

Thus the third term is 3

When n = 4

f(4) = f( 4 - 1) - 3

f(4) = f(3) - 3

f(4) = 3 - 3

f(4) = 0

Thus the fourth term is 0

Thus first three terms of sequence are 9 , 6 , 3

6 0
3 years ago
Multiple choice question, person that show's the most work gets brainliest, question is down below.
maria [59]

(- 1 + √3)/2

rationalise the denominator by multiplying the numerator/denominator by the conjugate of the denominator.

the conjugate of 1 + √3 is 1 - √3

(1 - √3)/(1 + √3)(1 - √3) = (1 - √3)/( 1² - (√3)²) = (1 - √3)/(1 - 3) = (1 - √3)/(- 2)

multiply numerator/denominator by (- 1)

=(-1 +√3)/2


4 0
3 years ago
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