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gladu [14]
3 years ago
11

The cheetah is the fastest land animal, capiable of attaining a speed of 110 km/h. In August 2009 , the world record for the men

's 100m sprint was set at 9.58 seconds. How many times is a cheetah as fast as the fastest human sprinter?
Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

About 3 times faster

Step-by-step explanation:

Cheetah's speed = 110 km / hr

World 100m sprint record :

Speed of sprinter :

Distance / time

100 m / 9.58s

= 10.438413 m/s

Convert Cheetah's speed to m/s

110 km/hr = (110 * 1000)m / (60 * 60 s)

= 110000 m / 3600 s

= 30.55555 m/s

Number of times cheetah is faster than sprinter :

30.55555 m/s ÷ 10.438413 m/s

= 2.927 times

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En una urna hay bolas numeradas del 0 al 99 (es decir: 0; 1; 2; 3... Hasta el 99). Juan y María realizan la experiencia de extra
dusya [7]

Answer:

Ambos tienen la misma probabilidad de lograr su objetivo y esa probabilidad es 0.81

Step-by-step explanation:

Se sabe que nuestra urna contiene bolas numeradas del 0 al 99. En total tenemos 100 bolas en nuestra urna.

Definimos los siguientes eventos :

J : '' El número extraído no incluye en su numeración la cifra 3 ''

M : '' El número extraído no incluye en su numeración la cifra 9 ''

Para saber quién tiene mayor probabilidad de lograr su objetivo debemos calcular la probabilidad de los eventos J y M.

Ahora bien, nuestro espacio muestral (Ω) está conformado por los siguientes elementos :

Ω = {0, 1 , 2 , ... , 99}

Donde cada uno de ellos tiene la misma probabilidad de ocurrencia. Estamos ante un espacio muestral equiprobable. Por ende, para calcular las respectivas probabilidades de los eventos J y M vamos a hacerlo mediante la siguiente fórmula :

P(J)=\frac{CasosFavorables}{CasosTotales}

Los casos totales son 100 (es el número de bolas numeradas en la urna).

Los casos favorables al evento J son 81 (son todos los números del 0 al 99 que no incluyen la cifra 3 en su numeración) ⇒

P(J)=\frac{81}{100}=0.81

La probabilidad del evento J es 0.81

De manera análoga, calculamos la probabilidad del evento M :

P(M)=\frac{CasosFavorables}{CasosTotales}=\frac{81}{100}=0.81

De igual manera, los casos totales siguen siendo 100.

Tenemos 81 números del 0 al 99 que no incluyen la cifra 9 en su numeración.

La probabilidad del evento M es 0.81

La probabilidad de ambos eventos es igual y vale 0.81

Finalmente, tanto Juan como María tienen la misma probabilidad de lograr su objetivo.

6 0
3 years ago
Consider the function f ( x ) = 1 − 4 x 2 on the interval [ − 1 , 3 ] . Find the average or mean slope of the function on this i
Blababa [14]

Answer:

The average slope is 8.

Step-by-step explanation:

Let <em>f</em> be defined on the closed interval [a, b]. The average slope of <em>f </em>between a and b is the quotient

                                       average slope = \frac{f(b)-f(a)}{b-a}

To find the average slope of the function f(x)=1-4x^2 on the interval [-1, 3] you have to evaluate your function in the interval and then divide by the interval.

So,

f(-1)=1-4(-1)^2=-3\\\\f(3)=1-4(3)^2=-35

The average slope is  \frac{f(3)-f(-1)}{3+1}= \frac{-3+35}{3+1}=\frac{32}{4}=8

4 0
3 years ago
Which is the quotient of 5 ÷ 1/4 ? Use the model to help. due TOMMOROW help
DaniilM [7]

The answer would be 1.25.

6 0
3 years ago
Look at the photo and answer the question.
Tanya [424]

Answer:

second option

Step-by-step explanation:

5 newton pushing it to the right

while a mere 4 newton pushing it to the left

more force pushing towards right

4 0
2 years ago
Read 2 more answers
A circle passes through the vertices of
Vika [28.1K]

Answer:

a) 14,1 cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

3 0
3 years ago
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