Answer:
Box B i think.
Step-by-step explanation:
Answer:
Can't see the attached image
Step-by-step explanation:
Post another question and make sure it has the image on it :)
Answer:
The answer is shown below
Step-by-step explanation:
Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.
a)

where k is the constant of proportionality, dy/dt = rate at which the rumor spreads
b)


At t = 2, y = 40% = 0.4
c) At y = 75% = 0.75

Answer:
0.8
Step-by-step explanation:
-2.8 + 3.6 = 0.8
Answer:
(x - 1)(x + 1)(x² + 1)
Step-by-step explanation:
Step 1: Factor Difference of Squares
(x² - 1)(x² + 1)
Step 2: Factor Difference of Squares for non-complex binomial root
(x - 1)(x + 1)(x² + 1)
And we have our answer!