Yen paid $10.50 for 2.5 pounds of pretzels. What price did she pay for each pound of pretzels?

You recently joined a nature club, and last week you went on a trip with the club into the countryside. Write an email to a friend about this. In your email, you should: . describe the place in the countryside you went to with the nature club explain what you learned during the trip to the countryside . invite your friend to join you on the next nature club trip. The pictures above may give you some ideas, and you can also use some ideas of your own. Your email should be between 150 and 200 words long. You will receive up to 8 marks for the content of your email, and up to 8 marks for the language used.

Step-by-step explanation:

You recently joined a nature club, and last week you went on a trip with the club into the countryside. Write an email to a friend about this. In your email, you should: . describe the place in the countryside you went to with the nature club explain what you learned during the trip to the countryside . invite your friend to join you on the next nature club trip. The pictures above may give you some ideas, and you can also use some ideas of your own. Your email should be between 150 and 200 words long. You will receive up to 8 marks for the content of your email, and up to 8 marks for the language used.

6 0

2 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$