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3 years ago

12

Tommy has 3 dogs. Last month, he bought 5 pounds of dog food for 7.95, 8 pounds of dog food for 12.72, and 15 pounds of dog food

for 23.85, what is the constant cost of the dog food per pound?

1 answer:

bija089 [108]3 years ago

8 0

Answer:

The constant cost of dog food is $1.59 per pound.

Step-by-step explanation:

Divide each pound by the cost and you get $1.59

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In circle O, what is m∠MAJ?

ira [324]

we know that

The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.

so

<u>Find the measure of the angle LAM</u>

m∠LAM is equal to

$\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees$

<u>Find the measure of the angle MAJ</u>

we know that

m∠LAM+m∠MAJ= $180$ ° ------> by supplementary angles

m∠MAJ= $(180-125)$

m∠MAJ= $55$ °

therefore

<u>the answer is</u>

The measure of the angle MAJ is $55\ degrees$

6 0

3 years ago

Read 2 more answers

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

First, find the volume for each bottle. Use 3.14 for pie or the pie button and round to the nearest hundredth. Volume of cylinde

marshall27 [118]

the volume of the cylinder is 572.27 cm³

Explanation:

Given:

radius of the cylinder = 4.5cm

height = 9cm

To get the volume of the cylinder, we will use the formula:

$\begin{gathered} Volume\text{ = \pi r^^b2h} \\ where\text{ \pi= 3.14} \\ r\text{ = radius, h = height} \end{gathered}$ $\begin{gathered} Volume\text{ of the cylinder = 3.14 }\times\text{ 4.5}^2\text{ }\times\text{ 9} \\ Volume\text{ of the cylinder = 3.14 }\times\text{ 182.25} \\ \\ Volume\text{ of the cylinder = 572.265 cm}^3 \end{gathered}$

To the nearest hundredth, the volume of the cylinder is 572.27 cm³

3 0

1 year ago

Mr. Jones is getting a 6% raise. If he made $720 a week, how much more will he make with the raise?

kirill115 [55]

$720 * .06 = 43.2

He will make $43.20 more each week.

7 0

3 years ago

Guys I need your help !!!

mars1129 [50]

Answer:

hope this helps you

a lot

have a great day..

4 0

2 years ago